JavaScript实现构造json数组的方法分析

本文实例讲述了JavaScript实现构造json数组的方法。分享给大家供大家参考，具体如下：

从后端拿到的数据是一个数组，每个元素中包含的数据如下(host相同的记录都是相邻的)

currentTime:"1470729601" host:"10.3.34.21" taskList:null taskNum:1

想构造类似如下结构的json数组

[{
 name: 'host:10.1.6.49',
 data: [
 [1470641461000, 5],
 [1470642581000, 4],
 [1470643701000, 2],
 [1470647341000, 3]
 ]
}, {
 name: 'host:10.3.34.18',
 data: [
 [1470641461000, 2],
 [1470642581000, 2],
 [1470643701000, 1],
 [1470647341000, 4]
 ]
}, {
 name: 'host:10.2.2.22',
 data: [
 [1470641461000, 3],
 [1470642581000, 2],
 [1470643701000, 6],
 [1470647341000, 4]
 ]
},{
 name: 'host:10.1.110.96',
 data: [
 [1470641461000, 1],
 [1470642581000, 8],
 [1470643701000, 1],
 [1470647341000, 1]
 ]
},{
 name: 'host:10.2.2.87',
 data: [
 [1470641461000, 7],
 [1470642581000, 3],
 [1470643701000, 6],
 [1470647341000, 5]
 ]
}]

错误的方式：

var backendData = data.result;
var resultList = new Array();
var curHost = "";
var oneHostDataList = new Array();
for (var i in backendData) {
 var host = backendData[i].host;
 if (host != curHost) {
 if(i != 0) {
 var item = new Object();
 item.name = curHost;
 item.data = oneHostDataList;
 resultList.push(item);
 }
 oneHostDataList = new Array();
 curHost = host;
 }
 else {
 var dot = new Array();
 dot.push(backendData[i].currentTime * 1000);
 dot.push(backendData[i].taskNum);
 oneHostDataList.push(dot);
 }
}
var item = new Object();
item.name = curHost;
item.data = oneHostDataList;
resultList.push(item);
$scope.data = JSON.stringify(resultList);

以上方式的问题在于转换后会使得name和host和带上引号，正确的方式如下：

var backendData = data.result;
var resultList = [];
var curHost = "";
var oneHostDataList = new Array();
for (var i in backendData) {
 var host = backendData[i].host;
 if (host != curHost) {
 if(i != 0) {
 var item = {
 name: curHost,
 data: oneHostDataList
 };
 resultList.push(item);
 }
 oneHostDataList = new Array();
 curHost = host;
 }
 else {
 var dot = new Array();
 dot.push(backendData[i].currentTime * 1000);
 dot.push(backendData[i].taskNum);
 oneHostDataList.push(dot);
 }
}
var item = new Object();
item.name = curHost;
item.data = oneHostDataList;
resultList.push(item);
$scope.data = resultList;

PS：这里再为大家推荐几款相关的json在线工具供大家参考：

在线JSON代码检验、检验、美化、格式化工具： http://tools.jb51.net/code/json

JSON在线格式化工具： http://tools.jb51.net/code/jsonformat

在线XML/JSON互相转换工具： http://tools.jb51.net/code/xmljson

json代码在线格式化/美化/压缩/编辑/转换工具： http://tools.jb51.net/code/jsoncodeformat

在线json压缩/转义工具： http://tools.jb51.net/code/json_yasuo_trans